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List Archives >  Maple User Group List Archive >  Archive by date >  This Month By Date >  This Month By Topic

[MUG] Solving equations with radicals

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[MUG] Solving equations with radicals
Author: PierLuigi Zezza    Posted: Sun, 28 Jul 2002 13:22:12 +0200

>> From: PierLuigi Zezza "pierluigi.zezza"

# I have some problems in understanding the behavior al Maple
> restart;
# Let us solve an equation with radicals
> eq:=a*x+sqrt(1-x^2)=0;
> assume(a,positive);
> sol:=[solve(eq,x)];
#

2
eq := a x + sqrt(1 - x ) = 0


1 1
sol := [-------------, - -------------]
2 2
sqrt(1 + a~ ) sqrt(1 + a~ )

# Maple find two solutions, the first one is wrong
> simplify(subs(x=sol[1],eq));

a~
2 ------------ = 0
2 1/2
(1 + a~ )

# The second is correct
> simplify(subs(x=sol[2],eq));

0 = 0

# The problem arises from "squaring" the radical and hence I try
> restart:
> with(RealDomain):
Warning, these protected names have been redefined and unprotected:
Im, Re, ^, arccos, arccosh, arccot, arccoth, arccsc, arccsch, arcsec,
arcsech, arcsin, arcsinh, arctan, arctanh, cos, cosh, cot, coth, csc,
csch, eval, exp, expand, limit, ln, log, sec, sech, signum, simplify,
sin, sinh, solve, sqrt, surd, tan, tanh

> eq:=a*x+sqrt(1-x^2)=0;
> assume(a,positive);
> sol:=solve(eq,x);

2
eq := a x + sqrt(1 - x ) = 0


1
sol := -------------
2
sqrt(1 + a~ )

# But in this way Maple finds only the wrong one and I do not understand
# way
# thanks
# gigi zezza


PierLuigi Zezza
"pzezza"

[View Complete Thread]



Previous by date: [MUG] Re: package for dynamics and nonlinear control, Jason Schattman
Next by date: [MUG] How to force a common factor from a simbolic matrix,  Nicolai Sirbu
Previous thread: [MUG] Number crunching testreport 4th edition, Stefan Steinhaus
Next thread: [MUG] How to force a common factor from a simbolic matrix,  Nicolai Sirbu



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