Author: Carl Devore
Posted: Thu, 19 Dec 2002 14:36:09 -0500
>> From: Carl Devore "devore"
On Mon, 16 Dec 2002, Ruan Zhichao wrote:
> kx^2/(x^2-x0^2)+ky^2/(y^2-y0^2)+kz^2/(z^2-z0^2)=0
> kx^2+ky^2+kz^2=1;
> x0,y0 and z0 are the given values. How to plot the two sufaces of (x,y,z)
It seems to me like you have 6 variables, {kx, ky, kz, x, y, z}, and 2
equations. This defines a 4-dimensional subset of 6-dimnesionl space, not
a surface. Or did you mean for k itself to be a variable?
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