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Re: [MATHCAD] V 8.03 are there bugs? or do I just need help?
| Re: [MATHCAD] V 8.03 are there bugs? or do I just need help? |
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Author: Albert_Stienstra
Posted: Fri, 1 Oct 1999 09:14:47 +0200
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A bit old, but it seems Mathcad 5+ gives the correct answers
Albert
(See attached file: forum19990930.mcd)
"William Hoffman" on 30-09-99 17:38:04
Please respond to />
To: />
cc: (bcc: Albert Stienstra/NL/I-O INC)
Subject: [MATHCAD] V 8.03 are there bugs? or do I just need help?
First, what are the verified bugs with version 8.03 of Mathcad? Of great
interest to me, are there ones in the symbolic portion. I believe, any
proven bugs that I learn about now may save me time in the future.
Second, I tried symbolically simplifying
((a^(-1)*b^3)/(a*b))^(-1/2)*((a*b^(-1))/(a^4*b^2)^(1/3). Can someone verify
if it's my mistake and Mathcad does simplify to 1/b^2 (Please send me your
file if Mathcad provides you the correct simplification).
Third, I tried solving 2=(x+y)/(x+xy) for x and MathCAD's solution provided
"not" x=y/(1+2y) but a solution with x on both sides of the equation. Again,
please can someone verify if it's my mistake and that Mathcad does solve to
the form that I need. (Please send me your file if Mathcad does provide you
the correct simplification).
Kind Regards,
William
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| Re: [MATHCAD] V 8.03 are there bugs? or do I just need help? |
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Author: Ray Girvan
Posted: Fri, 1 Oct 1999 11:51:53 +0100
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writes:
> "William Hoffman" />
>> Second, I tried symbolically simplifying
>> ((a^(-1)*b^3)/(a*b))^(-1/2)*((a*b^(-1))/(a^4*b^2)^(1/3). Can
>> someone verify if it's my mistake and Mathcad does simplify
>> to 1/b^2
> A bit old, but it seems Mathcad 5+ gives the correct answers
> Albert
> (See attached file: forum19990930.mcd)
Not exactly. From what William expects it to simplify to, his expression is:
[(a^-1*b^3)/(a*b)]^(-1/2) * [(a*b^-1)/(a^4*b^2)]^(1/3)
which simplifies to 1/SQRT(b^2/a^2) * [1/(a^3*b^3)]^(1/3)
My view is that the above is correct, the truly general answer, and
that 1/b^2 appears to discard, at all stages of simplification,
everything but the real positive branches. I've tried specifying all
this using "assume", but can't get it to work so far.
Ray
--
+++ Technical Author +++ Topsham, Devon, UK
http://www.users.zetnet.co.uk/rgirvan/ +++ The Apothecary's Drawer
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