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Re: [mathcad] Contouring irregular data
| Re: [mathcad] Contouring irregular data |
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Author: Tom Gutman
Posted: Thu, 24 Jul 2008 22:00:15 -0700
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When you have multiple plots in a graph each one can be a different
type. Usually you would not have more than one contour plot, which
will occupy the X-Y plane. To plot points over a contour plot they
would usually be plotted the usual way you would plot points -- as
scatter plots.
Tom Gutman
----- Original Message -----
From: "William J Marshall" />
To: />
Sent: Thursday, July 24, 2008 6:52 AM
Subject: Re: [mathcad] Contouring irregular data
>I can't help you on this question, Rob. But while we're on the
>subject of
> contour plots, I have not succeeded in placing (overlaying) a single
> data
> point on a contour plot. Does anybody have a hint?
>
> The Help page "Graphing Multiple 3D Plots" says you can add
> additional
> matrices to form additional plots, but it's not clear to me what the
> result would be for contour plots (interfering contours might
> require
> careful color choices, etc.). I tried adding a simple 3-element
> vector
> [x0, y0, z0] for my isolated 2nd point, but this didn't work. I see
> elsewhere in Help that "A plotted matrix must have at least two rows
> and
> two columns" so I'm going to try forming a triangle on the plot
> surface by
> expanding my vector to a 3x3 matrix with neighboring x and y values
> and
> identical z values. Mathcad might then recognize this as a dataset
> for
> which a contour can be defined.
>
> - Bill
>
> P.S. It looks like I may have answered my own question while typing
> a
> description of the problem. Well, that happens sometimes.
>
>
>
>
> Rob Beale />
> 07/24/2008 07:41 AM
> Please respond to
> />
>
>
> To
> />
> cc
>
> Subject
> [mathcad] Contouring irregular data
>
>
>
>
>
>
> I have data in the form of x,y and z coordinates which is bounded by
> a
> rectangular region from a set of experimental data. As the data is
> not
> defined over a regular grid is there any way that Mathcad can
> produce
> contour plots of the data?
>
> I look forward to hearing fro you
>
> Robert Beale
>
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