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[mathcad] 3d graphs for random functions

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[mathcad] 3d graphs for random functions
Author: =?iso-8859-2?Q?Damian_Ga=B3=EAziowski?=    Posted: Wed, 2 Apr 2008 12:18:08 +0200
Hey,

I need to make a 3d surface plot for my function, and i have problems with that. I didn't find the answear in similar topics so i decided to make a new one.

the function is:

G(x,y)=(sqrt(1+2*x^2*y^2))/sqrt((1-y^2)^2))

when i'm trying to create a plot, mathcad report me an error "divide by zero",
even when i'm setting x>0 and y>0

maybe formula is wrong, i don't know
all i want is to show how my variable G depends on x,y

G=(sqrt(1+2*x^2*y^2))/sqrt((1-y)^2))

and i want to make a plot ...G on Y axis, x on X, y on Z. What is the right formula...?How should i do this?

best regard!
Damien



RE: [mathcad] 3d graphs for random functions
Author: Neil Harris    Posted: Wed, 2 Apr 2008 12:31:28 +0100
Damien,



Your function becomes infinite at y = +/- 1, as 1 - y^2 = 0 at these values.



Neil





________________________________

From: Damian Gałęziowski "mailto:damian.galeziowski"
Sent: 02 April 2008 11:18
To: "mathcad"
Subject: [mathcad] 3d graphs for random functions



Hey,



I need to make a 3d surface plot for my function, and i have problems with that. I didn't find the answear in similar topics so i decided to make a new one.



the function is:



G(x,y)=(sqrt(1+2*x^2*y^2))/sqrt((1-y^2)^2))



when i'm trying to create a plot, mathcad report me an error "divide by zero",

even when i'm setting x>0 and y>0



maybe formula is wrong, i don't know


all i want is to show how my variable G depends on x,y



G=(sqrt(1+2*x^2*y^2))/sqrt((1-y)^2))



and i want to make a plot ...G on Y axis, x on X, y on Z. What is the right formula...?How should i do this?



best regard!

Damien








Re: [mathcad] 3d graphs for random functions
Author: =?iso-8859-2?Q?Damian_Ga=B3=EAziowski?=    Posted: Wed, 2 Apr 2008 17:45:54 +0200
helo Neil

problem is exactly when i'm setting y different from 1 and -1 stil the same error. "divide by zero"
have you checked it? do you have 3d surface graph to that?

Damien


ps. can you send me right definition of this function in mathcad?, parameters as well.
From: Neil Harris
To: "mathcad"
Sent: Wednesday, April 02, 2008 1:31 PM
Subject: RE: [mathcad] 3d graphs for random functions


Damien,



Your function becomes infinite at y = +/- 1, as 1 - y^2 = 0 at these values.



Neil







From: Damian Gałęziowski "mailto:damian.galeziowski"
Sent: 02 April 2008 11:18
To: "mathcad"
Subject: [mathcad] 3d graphs for random functions



Hey,



I need to make a 3d surface plot for my function, and i have problems with that. I didn't find the answear in similar topics so i decided to make a new one.



the function is:



G(x,y)=(sqrt(1+2*x^2*y^2))/sqrt((1-y^2)^2))



when i'm trying to create a plot, mathcad report me an error "divide by zero",

even when i'm setting x>0 and y>0



maybe formula is wrong, i don't know


all i want is to show how my variable G depends on x,y



G=(sqrt(1+2*x^2*y^2))/sqrt((1-y)^2))



and i want to make a plot ...G on Y axis, x on X, y on Z. What is the right formula...?How should i do this?



best regard!

Damien








RE: [mathcad] 3d graphs for random functions
Author: Neil Harris    Posted: Thu, 3 Apr 2008 10:47:30 +0100
Damien



If a divide by zero happens anywhere other than when y = +/- 1, then what you actually have is not the same as what you think you have.



Try the enclosed script.



Neil





________________________________

From: Damian Gałęziowski "mailto:damian.galeziowski"
Sent: 02 April 2008 16:46
To: "mathcad"
Subject: Re: [mathcad] 3d graphs for random functions



helo Neil



problem is exactly when i'm setting y different from 1 and -1 stil the same error. "divide by zero"

have you checked it? do you have 3d surface graph to that?



Damien





ps. can you send me right definition of this function in mathcad?, parameters as well.


From: Neil Harris "mailto:N.Harris"

To: "mathcad"

Sent: Wednesday, April 02, 2008 1:31 PM

Subject: RE: [mathcad] 3d graphs for random functions



Damien,



Your function becomes infinite at y = +/- 1, as 1 - y^2 = 0 at these values.



Neil






________________________________


From: Damian Gałęziowski "mailto:damian.galeziowski"
Sent: 02 April 2008 11:18
To: "mathcad"
Subject: [mathcad] 3d graphs for random functions



Hey,



I need to make a 3d surface plot for my function, and i have problems with that. I didn't find the answear in similar topics so i decided to make a new one.



the function is:



G(x,y)=(sqrt(1+2*x^2*y^2))/sqrt((1-y^2)^2))



when i'm trying to create a plot, mathcad report me an error "divide by zero",

even when i'm setting x>0 and y>0



maybe formula is wrong, i don't know


all i want is to show how my variable G depends on x,y



G=(sqrt(1+2*x^2*y^2))/sqrt((1-y)^2))



and i want to make a plot ...G on Y axis, x on X, y on Z. What is the right formula...?How should i do this?



best regard!

Damien








 Attachments:
 SurfacePlot.mcd


Re: [mathcad] 3d graphs for random functions
Author: =?iso-8859-2?Q?Damian_Ga=B3=EAziowski?=    Posted: Fri, 4 Apr 2008 09:43:37 +0200
helo Neil

thanx for help, now i see, and the script works.

Damien
From: Neil Harris
To: "mathcad"
Sent: Thursday, April 03, 2008 11:47 AM
Subject: RE: [mathcad] 3d graphs for random functions


Damien



If a divide by zero happens anywhere other than when y = +/- 1, then what you actually have is not the same as what you think you have.



Try the enclosed script.



Neil







From: Damian Gałęziowski "mailto:damian.galeziowski"
Sent: 02 April 2008 16:46
To: "mathcad"
Subject: Re: [mathcad] 3d graphs for random functions



helo Neil



problem is exactly when i'm setting y different from 1 and -1 stil the same error. "divide by zero"

have you checked it? do you have 3d surface graph to that?



Damien





ps. can you send me right definition of this function in mathcad?, parameters as well.


From: Neil Harris

To: "mathcad"

Sent: Wednesday, April 02, 2008 1:31 PM

Subject: RE: [mathcad] 3d graphs for random functions



Damien,



Your function becomes infinite at y = +/- 1, as 1 - y^2 = 0 at these values.



Neil







From: Damian Gałęziowski "mailto:damian.galeziowski"
Sent: 02 April 2008 11:18
To: "mathcad"
Subject: [mathcad] 3d graphs for random functions



Hey,



I need to make a 3d surface plot for my function, and i have problems with that. I didn't find the answear in similar topics so i decided to make a new one.



the function is:



G(x,y)=(sqrt(1+2*x^2*y^2))/sqrt((1-y^2)^2))



when i'm trying to create a plot, mathcad report me an error "divide by zero",

even when i'm setting x>0 and y>0



maybe formula is wrong, i don't know


all i want is to show how my variable G depends on x,y



G=(sqrt(1+2*x^2*y^2))/sqrt((1-y)^2))



and i want to make a plot ...G on Y axis, x on X, y on Z. What is the right formula...?How should i do this?



best regard!

Damien








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